Any All in Python

• Difficulty Level : Easy
• Last Updated : 25 Nov, 2020

Any and All are two built ins provided in python used for successive And/Or.

Any
Returns true if any of the items is True. It returns False if empty or all are false. Any can be thought of as a sequence of OR operations on the provided iterables.
It short circuit the execution i.e. stop the execution as soon as the result is known.

Syntax : any(list of iterables)

# Since all are false, false is returned

print (any([False, False, False, False]))

# Here the method will short-circuit at the

# second item (True) and will return True.

print (any([False, True, False, False]))

# Here the method will short-circuit at the

# first (True) and will return True.

print (any([True, False, False, False]))

Output :

FalseTrueTrue

All
Returns true if all of the items are True (or if the iterable is empty). All can be thought of as a sequence of AND operations on the provided iterables. It also short circuit the execution i.e. stop the execution as soon as the result is known.

Syntax : all(list of iterables)

# Here all the iterables are True so all

# will return True and the same will be printed

print (all([True, True, True, True]))

# Here the method will short-circuit at the 

# first item (False) and will return False.

print (all([False, True, True, False]))

# This statement will return False, as no

# True is found in the iterables

print (all([False, False, False]))

Output :

TrueFalseFalse

Practical Examples

# This code explains how can we 

# use 'any' function on list 

list1 = []

list2 = []

# Index ranges from 1 to 10 to multiply

for i in range(1,11):

    list1.append(4*i) 

# Index to access the list2 is from 0 to 9

for i in range(0,10):

    list2.append(list1[i]%5==0)

print('See whether at least one number is divisible by 5 in list 1=>')

print(any(list2))

Output:

See whether at least one number is divisible by 5 in list 1=>True

# Illustration of 'all' function in python 3

# Take two lists 

list1=[]

list2=[]

# All numbers in list1 are in form: 4*i-3

for i  in range(1,21):

    list1.append(4*i-3)

# list2 stores info of odd numbers in list1

for i in range(0,20):

    list2.append(list1[i]%2==1)

print('See whether all numbers in list1 are odd =>')

print(all(list2))

Output:

See whether all numbers in list1 are odd =>True